C++ Program to check a number is Armstrong or not using the function

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In this Program, You will learn how to check a number is Armstrong or not using the function in C++.

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Some list of Armstrong numbers: 153, 370, 371, 407

Example: How to check a number is Armstrong or not using the function in C++.

#include<iostream>
using namespace std;

int checkNumber(int n) {

    int r, rev = 0;
    while (n > 0) {
        r = n % 10;
        rev = rev + r * r*r;
        n = n / 10;
    }
    return rev;
}

int main() {

    int n, num;

    cout << "Enter a number:";
    cin>>n;

    num = checkNumber(n);
    if (num == n) {
        cout << "Number is ArmStrong:" << n;
    } else {
        cout << "The Number is not ArmStrong :" << n;
    }

    return 0;
}

Output:

Enter a number:153
Number is ArmStrong:153