C++ Program to find the sum of even and odd elements in the array

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In this program, You will learn how to find sum of even and odd elements in array in C++.

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for (i = 0; i < 10; i++) {

      if (arr[i] % 2 == 0) {

         //Statement
      }
 }

Example: How to find the sum of even and odd elements in an array in C++.

#include<iostream>
using namespace std;

int main() {

    int arr[5], i, seven = 0, sodd = 0;

    cout << "Enter 5 numbers:";
    for (i = 0; i < 5; i++) {
        cin >> arr[i];
    }

    for (i = 0; i < 5; i++) {
        if (arr[i] % 2 == 0) {
            seven = seven + arr[i];
        } else {
            sodd = sodd + arr[i];
        }
    }

    cout << "Sum of even:" << seven;
    cout << "\nSum of odd:" << sodd;

    return 0;
}

Output:

Enter 5 numbers:2 3 4 5 6
Sum of even:12
Sum of odd:8