C++ Program to find the sum of even and odd elements in the array using the function

---

In this program, You will learn how to find the sum of even and odd elements in an array using the function in C++.

---

List is: 2 3 22 11 44

Even the sum is: 68

The odd sum is: 14

Example: How to find the sum of even and odd elements in the array using a function in C++.

#include<iostream>
using namespace std;

void findSum(int arr[], int n) {

    int se = 0, sod = 0;
    for (int i = 0; i < n; i++) {
        if (arr[i] % 2 == 0) {
            se = se + arr[i];
        } else {
            sod = sod + arr[i];
        }
    }
    cout << "Sum of even array element:" << se;
    cout << "\nSum of odd array element:" << sod;
}

int main() {

    int arr[10], i, n;

    cout << "Enter size of an array:";
    cin>>n;

    cout << "Enter array elements:";
    for (i = 0; i < n; i++) {
        cin >> arr[i];
    }

    findSum(arr, n);

    return 0;
}

Output:

Enter size of an array:5
Enter array elements:2 3 4 5 6
Sum of even array element:12
Sum of odd array element:8