C++ Program to find the sum of even and odd elements in the array


In this program, You will learn how to find sum of even and odd elements in array in C++.


for (i = 0; i < 10; i++) {

      if (arr[i] % 2 == 0) {

         //Statement
      }
 }

Example: How to find the sum of even and odd elements in an array in C++.

#include<iostream>
using namespace std;

int main() {

    int arr[5], i, seven = 0, sodd = 0;

    cout << "Enter 5 numbers:";
    for (i = 0; i < 5; i++) {
        cin >> arr[i];
    }

    for (i = 0; i < 5; i++) {
        if (arr[i] % 2 == 0) {
            seven = seven + arr[i];
        } else {
            sodd = sodd + arr[i];
        }
    }

    cout << "Sum of even:" << seven;
    cout << "\nSum of odd:" << sodd;

    return 0;
}

Output:

Enter 5 numbers:2 3 4 5 6
Sum of even:12
Sum of odd:8