C# Program to perform arithmetic operations using switch case
In this program, You will learn how to perform arithmetic operations using a switch case in C#.
switch (choice) {
//statement
}
Example: How to perform arithmetic operations using a switch case in C#.
using System;
public class Test
{
public static void Main(string[] args)
{
int x, y, res;
int ch;
Console.WriteLine("Enter 1 For Addition :");
Console.WriteLine("Enter 2 For Subtraction :");
Console.WriteLine("Enter 3 For Multiplication :");
Console.WriteLine("Enter 4 For Division :");
Console.WriteLine("Enter 5 For Mode :");
ch = Convert.ToInt32(Console.ReadLine());
switch (ch)
{
case 1:
{
Console.WriteLine("Enter Two Numbers :");
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
res = x + y;
Console.WriteLine("Result is :" + res);
break;
}
case 2:
{
Console.WriteLine("Enter Two Numbers :");
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
res = x - y;
Console.WriteLine("Result is :" + res);
break;
}
case 3:
{
Console.WriteLine("Enter Two Numbers :");
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
res = x * y;
Console.WriteLine("Result is :" + res);
break;
}
case 4:
{
Console.WriteLine("Enter Two Numbers :");
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
res = x / y;
Console.WriteLine("Result is :" + res);
break;
}
case 5:
{
Console.WriteLine("Enter Two Numbers :");
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
res = x % y;
Console.WriteLine("Result is :" + res);
break;
}
}
}
}
Output:
Enter 1 For Addition :
Enter 2 For Subtraction :
Enter 3 For Multiplication :
Enter 4 For Division :
Enter 5 For Mode :
1
Enter Two Numbers :
10
5
Result is :15