Java Program to find the sum of digits of a number using recursion


In this program, you will learn how to find the sum of digits of a number using recursion in Java.


4321 => 4 + 3 + 2 + 1

1232 => 1 + 2 + 3 + 2


Example: How to find the sum of digits of a number using recursion in Java

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import java.util.Scanner;

class Main {
    int s = 0, r;

    int sumOfDigits(int n) {

        if (n > 0) {
            r = n % 10;
            s = s + r;
            sumOfDigits(n / 10);
        }

        return s;
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        System.out.print("Enter a number : ");
        int n = sc.nextInt();

        Main obj = new Main();
        int sum = obj.sumOfDigits(n);

        System.out.println("\nSum of digits : " + sum);

    }
}

Output:

Enter a number : 4321
Sum of digits : 10