Java Program to find the second largest number in an array

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In this program, You will learn how to find the second largest number in an array in java.

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List is: 1 2 3 4 5

The second-largest number is: 4

Example: How to find the second largest number in an array in java.

import java.util.Scanner;

class Main {
    public static void main(String args[]) {

        Scanner s = new Scanner(System.in);
        int a[] = new int[100];
        int n, largest = 0, slargest = -1;

        System.out.print("Enter size of an array:");
        n = s.nextInt();

        System.out.print("Enter array elements:");

        for (int i = 0; i < n; i++) {
            a[i] = s.nextInt();
        }
        for (int i = 0; i < n; i++) {
            if (largest <= a[i]) {
                largest = a[i];
            }
        }

        for (int i = 0; i < n; i++) {
            if (slargest <= a[i] && a[i] < largest) {
                slargest = a[i];
            }
        }

        System.out.print("Second Largest number:" + slargest);
    }
}

Output:

Enter size of an array:5
Enter array elements:20 30 40 50 10
Second Largest number:40